As subtle as a flying brick.

Posts tagged “Computer file

How to clean up dated folders

Suppose you have a backup directory with backup snapshots named by timestamp:

$ ls
2013-05-03-103022
2013-05-04-103033
2013-05-05-103023
2013-05-06-103040
2013-05-07-103022

You want to remove snapshots older than 3 days. The one-liner does it:

$ date
Tue May  7 13:50:57 KST 2013
$ ls | grep '....-..-..-......' | sort | xargs -I {} bash -c "[[ x{} < x$(date -d '3 days ago' +%Y-%m-%d-%H%M%S) ]] && rm -rfv {}"
removed directory: `2013-05-03-103022'
removed directory: `2013-05-04-103033'

 

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Understanding /etc/shadow file

Q. Can you explain /etc/shadow file used under Linux or UNIX?

A. /etc/shadow file stores actual password in encrypted format for user’s account with additional properties related to user password i.e. it stores secure user account information.

All fields are separated by a colon (:) symbol. It has one entry per line for each user listed in /etc/passwd file Generally, shadow file entry looks as follows:

shadow-file

(Fig.01: /etc/shadow file fields)

  1. User name : It is your login name
  2. Password: It your encrypted password. The password should be minimum 6-8 characters long including special characters/digits
  3. Last password change (lastchanged): Days since Jan 1, 1970 that password was last changed
  4. Minimum: The minimum number of days required between password changes i.e. the number of days left before the user is allowed to change his/her password
  5. Maximum: The maximum number of days the password is valid (after that user is forced to change his/her password)
  6. Warn : The number of days before password is to expire that user is warned that his/her password must be changed
  7. Inactive : The number of days after password expires that account is disabled
  8. Expire : days since Jan 1, 1970 that account is disabled i.e. an absolute date specifying when the login may no longer be used

The last 6 fields provides password aging and account lockout features (you need to use chage command to setup password aging). According to man page of shadow – the password field must be filled. The encrypted password consists of 13 to 24 characters from the 64 character alphabet a through z, A through Z, 0 through 9, \. and /. Optionally it can start with a “$” character. This means the encrypted password was generated using another (not DES) algorithm. For example if it starts with “$1$” it means the MD5-based algorithm was used.


Get only the latest version of a file from across mutiple directories

bash$ find . -name custlist\* | perl -ne '$path = $_; s?.*/??; $name = $_; $map{$name} = $path; ++$c; END { print $map{(sort(keys(%map)))[$c-1]} }'

Explanation

The purpose of this is to find the the “latest” version of the custlist_*.xls file from among multiple versions in directories and sub-directories, for example:

./c/custlist_v1.003.xls
./c/custlist_v2.001.xls
./d/b/custlist_v1.001.xls
./d/custlist_v1.002.xls

Let’s decompose the one-liner to the big steps:

  • find . -name custlist\* — find the files matching the target pattern
  • ... | perl -ne '...' — run perl, with the input wrapped around in a while loop so that each line in the input is set in the variable $_
  • $path = $_; s?.*/??; $name = $_; — save the full path in $path, and cut off the subdirectory part to get to the base name of the file and save it in $name
  • $map{$name} = $path; — build a mapping of $name to $path
  • ++$c; — we count the elements, to use it later
  • (sort(keys(%map)))[$c-1] — sort the keys of the map, and get the last element, which is custlist_v2.001.xls in this example
  • END { print $map{$last} }' — at the end of all input data, print the path of the latest version of the file

Limitations

Even if the latest version of the file appears multiple times in the directories, the one-liner will print only one of the paths. This could be fixed though if needed.


Bash For Loop Examples

How do I use bash for loop to repeat certain task under Linux / UNIX operating system? How do I set infinite loops using for statement? How do I use three-parameter for loop control expression?

A ‘for loop’ is a bash programming language statement which allows code to be repeatedly executed. A for loop is classified as an iteration statement i.e. it is the repetition of a process within a bash script.

For example, you can run UNIX command or task 5 times or read and process list of files using a for loop. A for loop can be used at a shell prompt or within a shell script itself.

for loop syntax

Numeric ranges for syntax is as follows:

for VARIABLE in 1 2 3 4 5 .. N
do
	command1
	command2
	commandN
done

This type of for loop is characterized by counting. The range is specified by a beginning (#1) and ending number (#5). The for loop executes a sequence of commands for each member in a list of items. A representative example in BASH is as follows to display welcome message 5 times with for loop:

#!/bin/bash
for i in 1 2 3 4 5
do
   echo "Welcome $i times"
done

Sometimes you may need to set a step value (allowing one to count by two’s or to count backwards for instance). Latest bash version 3.0+ has inbuilt support for setting up ranges:

#!/bin/bash
for i in {1..5}
do
   echo "Welcome $i times"
done

Bash v4.0+ has inbuilt support for setting up a step value using {START..END..INCREMENT} syntax:

#!/bin/bash
echo "Bash version ${BASH_VERSION}..."
for i in {0..10..2}
  do
     echo "Welcome $i times"
 done

Sample outputs:

Bash version 4.0.33(0)-release...
Welcome 0 times
Welcome 2 times
Welcome 4 times
Welcome 6 times
Welcome 8 times
Welcome 10 times

The seq command (outdated)

WARNING! The seq command print a sequence of numbers and it is here due to historical reasons. The following examples is only recommend for older bash version. All users (bash v3.x+) are recommended to use the above syntax.

The seq command can be used as follows. A representative example in seq is as follows:

#!/bin/bash
for i in $(seq 1 2 20)
do
   echo "Welcome $i times"
done

There is no good reason to use an external command such as seq to count and increment numbers in the for loop, hence it is recommend that you avoid using seq. The builtin command are fast.

Three-expression bash for loops syntax

This type of for loop share a common heritage with the C programming language. It is characterized by a three-parameter loop control expression; consisting of an initializer (EXP1), a loop-test or condition (EXP2), and a counting expression (EXP3).

for (( EXP1; EXP2; EXP3 ))
do
	command1
	command2
	command3
done

A representative three-expression example in bash as follows:

#!/bin/bash
for (( c=1; c<=5; c++ ))
do
	echo "Welcome $c times..."
done

Sample output:

Welcome 1 times
Welcome 2 times
Welcome 3 times
Welcome 4 times
Welcome 5 times

How do I use for as infinite loops?

Infinite for loop can be created with empty expressions, such as:

#!/bin/bash
for (( ; ; ))
do
   echo "infinite loops [ hit CTRL+C to stop]"
done

Conditional exit with break

You can do early exit with break statement inside the for loop. You can exit from within a FOR, WHILE or UNTIL loop using break. General break statement inside the for loop:

for I in 1 2 3 4 5
do
  statements1      #Executed for all values of ''I'', up to a disaster-condition if any.
  statements2
  if (disaster-condition)
  then
	break       	   #Abandon the loop.
  fi
  statements3          #While good and, no disaster-condition.
done

Following shell script will go though all files stored in /etc directory. The for loop will be abandon when /etc/resolv.conf file found.

#!/bin/bash
for file in /etc/*
do
	if [ "${file}" == "/etc/resolv.conf" ]
	then
		countNameservers=$(grep -c nameserver /etc/resolv.conf)
		echo "Total  ${countNameservers} nameservers defined in ${file}"
		break
	fi
done

Early continuation with continue statement

To resume the next iteration of the enclosing FOR, WHILE or UNTIL loop use continue statement.

for I in 1 2 3 4 5
do
  statements1      #Executed for all values of ''I'', up to a disaster-condition if any.
  statements2
  if (condition)
  then
	continue   #Go to next iteration of I in the loop and skip statements3
  fi
  statements3
done

This script make backup of all file names specified on command line. If .bak file exists, it will skip the cp command.

#!/bin/bash
FILES="$@"
for f in $FILES
do
        # if .bak backup file exists, read next file
	if [ -f ${f}.bak ]
	then
		echo "Skiping $f file..."
		continue  # read next file and skip cp command
	fi
        # we are hear means no backup file exists, just use cp command to copy file
	/bin/cp $f $f.bak
done

Recommended readings:

  • man bash
  • help for
  • help {
  • help break
  • help continue

Updated for accuracy!